2x^2-19x+24=24

Solution for 2x^2-19x+24=24 equation:

2x^2-19x+24=24

We move all terms to the left:

2x^2-19x+24-(24)=0

We add all the numbers together, and all the variables

2x^2-19x=0

a = 2; b = -19; c = 0;
Δ = b2-4ac
Δ = -192-4·2·0
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-19}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+19}{2*2}=\frac{38}{4}
=9+1/2
$